WebOct 26, 2024 · Now I'm trying to determine the value of K so that I have a marginally stable system. I'm not supposed to use the Routh-Hurwitz method. I'm thinking hard but I seem … WebMay 23, 2016 · Since it is given that you have to find suitable k for the problem to have unique solution asserts that problem has already unique solution. i.e. rank of matrix = rank of augmented matrix = no. of unknowns=3. i.e. rank of matrix should be 3.means determinant should be non zero.rank of augmented matrix should be 3 as well and rank of …
Chapter 8 HW Solution - University of New Mexico
WebExpert Answer. Transcribed image text: Determine for what values of k the system has (a) a unique solution: (b) no solution; (c) infinitely many solutions. 5x + 3y = 0 15x + ky = 0 (a) For what value (s) of k does the system have a unique solution? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. WebSenior Product Manager, Platform Optimization and Instrumentation -- Support senior leadership to extend features and remediate gaps in our learning platforms -- Work with customer, product, and ... inbrengen thoraxdrain
Determine the value of k for which the system of linear ... - Wyzant
WebOct 26, 2024 · Now I'm trying to determine the value of K so that I have a marginally stable system. I'm not supposed to use the Routh-Hurwitz method. I'm thinking hard but I seem to get to nowhere. I know that for the system to be marginally stable I will need a real pole in the left complex plane and two complex conjugate pure imaginary poles. WebSep 14, 2014 · This determinant can be worked out by hand resulting in the equation. 2k - 8 + 55 -40 +22 - k = 0. The solution is k = -29. With k = -29 there are two possibilities. There could be no solution or an infinite number of solutions. If the latter (which we would like to rule out), there will be a solution for which z = 0. WebFeb 2, 2015 · Now a reasonable step would be to divide the last row by ( k − 1). But this is only possible if k − 1 ≠ 0. So you can: Solve the case k = 1 separately. For k ≠ 1 divide … inclination\u0027s r